Question #108572

A particle P is let fall vertically from a height to the ground. Another particle Q is projected vertically down 3s later with a velocity of 3m/s^s from the same height. If both particles reached the ground simultaneously. Calculate:

a. time by each particle to reach the ground

b. distance travelled by each particle to reach the ground.

a. time by each particle to reach the ground

b. distance travelled by each particle to reach the ground.

Expert's answer

Let time taken by first particle be "t."

If second particle is projected with velocity"=3\\frac{m}{sec}"

For first particle, "d=\\frac{1}{2}gt^2"

For second particle, "d=3(t-3)+\\frac{1}{2}g(t-3)^2"

Equating both the equations, we get

"\\frac{1}{2}gt^2=3(t-3)+\\frac{1}{2}g(t-3)^2"

"t=\\frac{4}{3}sec"

Putting "t=\\frac{4}{3}sec" in any of the equations, we get "d=\\frac{80}{9}m"

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Karim Waris01.04.21, 20:39Good

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