Question #108465

A direct compressive force of 240,000 N is applied to a solid piece of material of rectangular cross-section, 8 cm by 5 cm.

Expert's answer

Given that,

A direct compressive force of 240,000 N is applied to a solid piece of material of rectangular cross-section, 8 cm by 5 cm.

Therefore the total cross sectional area = "8cm\\times5cm=40cm^2"

Pressure acting on the solid piece of material by the compressive force is given by,

"P=\\frac{F}{A}=\\frac{240000}{40 \\times 10^{-4}}"

"=6\\times10^{7}Nm^{-2}"

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