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Answer to Question #107839 in Mechanics | Relativity for Jimmy

Question #107839
Calculate the period of a simple pendulum of length 0.5m in a place were the acceleration due to gravity is 10ms-2
1
Expert's answer
2020-04-06T08:41:55-0400

The period of simple pendulum

"T=2\\pi \\sqrt{\\frac{l}{g}}=2\\pi \\sqrt{\\frac{0.5}{10}}=1.4\\:\\rm s."

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