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# Answer to Question #107658 in Mechanics | Relativity for artem

Question #107658
A 0.5 kg water balloon is dropped from a balcony 40 meters from the ground. What is the balloon's velocity just as it hits the ground? (Ignoring air resistance)
1
Expert's answer
2020-04-03T13:24:06-0400

Ignoring the air resistance means the case of free fall (gravity is the only force acting upon body).

"h=v_0 t+\\frac{gt^2}{2}"

and

"v=v_0+gt",

where "h" - height, m; "v" - velocity, m/s; "v_0" - initial velocity, m/s; "t" - time, s; "g" - acceleration due to gravity, m/s2 ("g \\approx 9.8 \\; m\/s^2"). In our case "v_0 =0", so balloon will hit the ground at

"t= \\sqrt{\\frac{2h}{g}}"

"v=g \\cdot \\sqrt{\\frac{2h}{g}} = \\sqrt{2gh}"

"v=\\sqrt{2 \\cdot 9.8 \\cdot 40} = \\sqrt{784} = 28 \\; m\/s"

Answer: 28 m/s.

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