Question #1069

A 224 kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.25, calculate the acceleration of the crate.

Expert's answer

According the Second Newton's law

ma = F - μ mg;

a = F/m - μ g = 710/224 - 0.25* 10 = 0.67 m/s^{2}

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ma = F - μ mg;

a = F/m - μ g = 710/224 - 0.25* 10 = 0.67 m/s

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