Answer to Question #10556 in Mechanics | Relativity for sunil kumar
The answer depends on a direction the second stone was thrown.
Anyhow, the first stone flight time is
t = √(2H/g) = √(2·100/9.8) ≈ 4.5175 s.
If the second stone was thrown horizonatally down, it reached the ground earlier then the first one, so the meeting time is 4.5175s and meeting height is 0m.
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