Answer to Question #10512 in Mechanics | Relativity for sabrina
Same with down and up: 10N + 50N - 30N = 30N down.
The magnitude of the net force is
F = √(10²+30²) = √1000 ≈ 31.6228 N.
The angle between the net force and the east direction is
& alpha; = 180° + asin(30/31.6228) ≈ 251.5651°.
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