Answer to Question #10496 in Mechanics | Relativity for prakhar
Let V be the speed and Vhor is the horizontal component of the speed
of rain drops, and A be the angle between rain's direction and the normal direction.
Vhor = V·sinA.
Vhor = Vm1 = 2km/h
V·sin45 = Vm2
V = Vm2 / sin45 = 4 / sin45 = 5.6569 km/h
V·sinA = Vm1
A = asin(Vm1/V) = asin(2/5.6569) = asin(0.3536) = 20.7046°.
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