# Answer to Question #10395 in Mechanics | Relativity for prakhar

Question #10395

to a man walking due east at the rate of 2km/h ,rain drops to fall vertically and when he increase his speed to 4km/h ,it appears to meet him at 25degree find real direction and speed of rain?

Expert's answer

Let Vm is the speed of man.

Let V is the speed and Vhor is the horizontal

component of the speed

of rain drops, A as the angle between rain's direction

and the normal.

Vhor = V * sinA.

Vhor = Vm1

V * sin25 = Vm2

V = Vm2

/ sin25 = 4 / sin25 = 9.4648 km/h

V * sinA = Vm1

A = asin(Vm1 / V) =

asin(0.2113) = 12.1991 degrees.

Let V is the speed and Vhor is the horizontal

component of the speed

of rain drops, A as the angle between rain's direction

and the normal.

Vhor = V * sinA.

Vhor = Vm1

V * sin25 = Vm2

V = Vm2

/ sin25 = 4 / sin25 = 9.4648 km/h

V * sinA = Vm1

A = asin(Vm1 / V) =

asin(0.2113) = 12.1991 degrees.

## Comments

## Leave a comment