Answer to Question #10395 in Mechanics | Relativity for prakhar
Let V is the speed and Vhor is the horizontal
component of the speed
of rain drops, A as the angle between rain's direction
and the normal.
Vhor = V * sinA.
Vhor = Vm1
V * sin25 = Vm2
V = Vm2
/ sin25 = 4 / sin25 = 9.4648 km/h
V * sinA = Vm1
A = asin(Vm1 / V) =
asin(0.2113) = 12.1991 degrees.
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