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# Answer to Question #103285 in Mechanics | Relativity for Sam

Question #103285
two curling stones collide on an ice rink. stone 1 has a mass of 20kg and is moving north. Stone 2 was at rest initially. the stones collide dead center, sending stone 1 at 0.35 m/s and giving stone 2 a final velocity of 0.75 m/s to the north. Find the mass of stone 2 and the initial velocity of stone 1.
1
2020-02-18T09:58:44-0500

Given:

"m_1=20\\:\\rm kg;"

"v_2=0\\:\\rm m\/s;"

"v_1'=0.35\\:\\rm m\/s;"

"v_2'=0.75\\:\\rm m\/s."

The law of conservation of momentum states

"m_1{\\bf v}_1+m_2{\\bf v}_2=m_1{\\bf v}_1'+m_2{\\bf v}_2'."

The law of conservation of energy states

"\\frac{m_1v_1^2}{2}+\\frac{m_2v_2^2}{2}=\\frac{m_1v_1'^2}{2}+\\frac{m_2v_2'^2}{2}."

In our case, we get equations

"20v_1=20\\times 0.35+m_2\\times 0.75."

"20v_1^2=20\\times 0.35^2+m_2\\times 0.75^2."

Solution:

"v_1=0.4\\:\\rm m\/s;"

"m_2=1.3\\:\\rm kg."

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