Question #102731

The bulk modulus of a block of copper is 1.3 GPa. When a pressure of 1.8 MPa is applied to the 1.0 m^3 block, its volume decreases by how much?

Expert's answer

"K=-V_0\\frac{\\Delta p}{\\Delta V}"

**Given.**

"K=1.3 GPa"

"p_0=101325 Pa"

"p=1.8 MPa"

"V_0=1 m^3"

"\\Delta V=-V_0\\frac{p-p_0}{K}=-1\\cdot \\frac{1800000-101325}{1.3\\cdot10^9}\\approx-0.00131 m^3=-1310 cm^3"

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