Answer to Question #102699 in Mechanics | Relativity for teri

Question

Calculate the depth in the ocean at which the pressure is three times atmospheric pressure. Atmospheric pressure is 1.013 × 105 Pa. The acceleration of gravity is 9.81 m/s2 and the density of sea water is 1025 kg/m3 .
Answer in units of m.

Answer 1

$$p_0 +ρgh=3p_0 ​$$

$$ρgh=2p_0$$

$$(1025)(9.81)h=2(1.013⋅10^5 )$$

$$h=20.15 m$$