Question #102688

A ball of mass kg,.10 starting from rest, falls a height of 4.0 m and then collides with the ground. After the collision, the ball bounces up to a height of 2.0 m. The collision with the ground takes place over a time 4.0 × 10 -³s Determine (i) the momentum of the ball immediately before the collision and immediately after the collision and (ii) the average force exerted by the ground on the ball. Take g = 10.0m/s².

Expert's answer

Upwards is the positive direction.

i)

"p_i=-10\\sqrt{2(10)(4)}=-89.4\\frac{kg\\cdot m}{s}"

"p_f=mv_f=m\\sqrt{2gh_f}"

"p_f=10\\sqrt{2(10)(2)}=63.2\\frac{kg\\cdot m}{s}"

ii)

"F=\\frac{63.2-(-89.4)}{0.004}=38200\\ N=38.2\\ kN"

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