Answer to Question #102039 in Mechanics | Relativity for bjbnl

Question #102039

A 7.65 kg bowling ball traveling at 12.65 m/s strikes a 1.7 kg bowling pin. The impact slows the bowling ball to 10.13 m/s.

Determine the change in momentum of the pin.

Expert's answer

"P=M(v_f-v_i)"

"P=7.65(12.65-10.13)=19.3\\frac{kg\\cdot m}{s}"

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