# Answer to Question #10092 in Mechanics | Relativity for tammy

Question #10092

gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy

Expert's answer

A glonkin weighs 0.911 troy ounces.

So 100.0 glonkins = 91.1 troy

ounces.

There are 31.1 grams in a troy ounce, and gold has a density of

19.3

grams / cc. 1 cc = 1 mL.

So,

V = (91.1 oz * 31.1 g/oz) / 19.3 g

/mL = 146.8 mL = 0.1468 L

So 100.0 glonkins = 91.1 troy

ounces.

There are 31.1 grams in a troy ounce, and gold has a density of

19.3

grams / cc. 1 cc = 1 mL.

So,

V = (91.1 oz * 31.1 g/oz) / 19.3 g

/mL = 146.8 mL = 0.1468 L

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment