gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy
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Expert's answer
2012-05-29T08:29:36-0400
A glonkin weighs 0.911 troy ounces. So 100.0 glonkins = 91.1 troy ounces. There are 31.1 grams in a troy ounce, and gold has a density of 19.3 grams / cc. 1 cc = 1 mL. So, V = (91.1 oz * 31.1 g/oz) / 19.3 g /mL = 146.8 mL = 0.1468 L
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