Question #100378
A helical spring is extended by a force which increase uniformally from 0 to 600 newtons. The corresponding extension of the spring is 200mm. What is the total work done?
1
Expert's answer
2019-12-13T10:09:37-0500

W=0.5FxW=0.5Fx

W=0.5(600)(0.2)=60 JW=0.5(600)(0.2)=60\ J


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: Field Theory

Comments

No comments. Be the first!
Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Canada #339914 on Dec 2023