# Answer on Electromagnetism Question for siddharth kapoor

Question #7212

negative point charge 10-8 coulomb is situated in air at the origin of a rectangular coordinate system. What is the electric field intensity at a point on the positive x direction 3 metres from the origin?

Expert's answer

Let's provide some denominations:

q = - 10^(-8) coulomb - the charge of the point

r = 3m - distance from the point

The intensity of the electric field is

E = k*q/r² = 8.9877*(-10^(-8))/3² = 8.9877*10^(-8)/9 = 0.99863*10^(-8) N/coulomb.

q = - 10^(-8) coulomb - the charge of the point

r = 3m - distance from the point

The intensity of the electric field is

E = k*q/r² = 8.9877*(-10^(-8))/3² = 8.9877*10^(-8)/9 = 0.99863*10^(-8) N/coulomb.

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