Answer to Question #61562 in Electricity and Magnetism for Sakura

Question

As the electrons are accelerated through the second anode, the gain in kinetic energy is 1.98X10^-15J, and the speed of the electrons as they enter the region between the electric field plates is 6.60X10^7m/s. The electrons are moving to the right as they pass between the electric field plates. The plates are 2.00cm long, 2.00mm apart, and as the electrons pass between the plates, the potential difference is 4.50X10^2V. The top plate of the electric field is positive charged.
a)Determine the acceleration of the electron in the region between the deflection plates. Include both magnitude and direction in your answer.
b)Determine the vertical component of the velocity of the electrons when they emerge from the region between the plates. Include both magnitude and direction in your answer.
c)Determine the vertical displacement of the electrons as they are deflected. Include both magnitude and direction in your answer.