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Answer to Question #40683 in Electromagnetism for Sanjeev

Question #40683
A BEAM OF PROTON PASSES THRU A REGION OF UNIFORM MAGNETIC FIELD = 0.01 T.IT CROSSES A SCREEN 10 cm WIDE . IN ORDER TO PREVENT THE BEAM FROM CROSSING THE SCREEN , BEAM IS ROTATED BY 30o. WHAT IS THE MAX. SPEED OF THE PROTONS IN THE BEAM ?

1.1.11 * 10^6 m/s

2. 1.11 * 10^5 m/s

3. 2.92* 10^6 m/s

4. 2.92 * 10^5 m/s

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Assignment Expert
01.04.14, 15:51

Dear Sanjeev,

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Diagram shows the trajectory of proton in the region with magnetic field B. Horizontal lines are borders of this region. Arrows show direction of the Lorentz force F = qVB (Eq. 1) and proton's velocity. Radius R shows the arc trajectory with arc angle alpha of proton.

Sanjeev
31.03.14, 19:26

Unable to understand the diagram. Rest answer is explained very well.

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