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Answer to Question #40683 in Electricity and Magnetism for Sanjeev
Question #40683
A BEAM OF PROTON PASSES THRU A REGION OF UNIFORM MAGNETIC FIELD = 0.01 T.IT CROSSES A SCREEN 10 cm WIDE . IN ORDER TO PREVENT THE BEAM FROM CROSSING THE SCREEN , BEAM IS ROTATED BY 30o. WHAT IS THE MAX. SPEED OF THE PROTONS IN THE BEAM ?
1.1.11 * 10^6 m/s
2. 1.11 * 10^5 m/s
3. 2.92* 10^6 m/s
4. 2.92 * 10^5 m/s
1.1.11 * 10^6 m/s
2. 1.11 * 10^5 m/s
3. 2.92* 10^6 m/s
4. 2.92 * 10^5 m/s
Expert's answer
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Comments
Dear Sanjeev, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you! Diagram shows the trajectory of proton in the region with magnetic field B. Horizontal lines are borders of this region. Arrows show direction of the Lorentz force F = qVB (Eq. 1) and proton's velocity. Radius R shows the arc trajectory with arc angle alpha of proton.
Unable to understand the diagram. Rest answer is explained very well.
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