Answer to Question #350110 in Electricity and Magnetism for wafa

Question #350110

The maximum kinetic energy of emitted photoelectrons in a photoelectric cell is 7.5X10-19 J. What is the stopping 

1
Expert's answer
2022-06-13T08:23:34-0400
"W=eV"

"V=\\frac{W}{e}=\\frac{7.5*10^{-19}\\:\\rm J}{1.6*10^{-19}\\:\\rm C}=4.7\\:\\rm V"


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