Question #33279
a charged particle moving in a perpendicular uniform magnetic field penetrates a layer of head and there by looses half of its kinetic energy . how will the radius of its path change?
Expert's answer
If the kinetic energy was reduced 2 times, then velocitywas reduced sqrt(2) times, because
E=mv^2/2
the radius is related to velocity as
r = mv/qB
where m is mass, B is magnetic field and q is charge. If all these values stay the same, then change in radius is also in sqrt(2) times, as velocity is, because it is proportional to it.
Answer: radius will become sqrt(2) times smaller.
E=mv^2/2
the radius is related to velocity as
r = mv/qB
where m is mass, B is magnetic field and q is charge. If all these values stay the same, then change in radius is also in sqrt(2) times, as velocity is, because it is proportional to it.
Answer: radius will become sqrt(2) times smaller.
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#339914 on Dec 2023
#339914 on Dec 2023
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