Question #2434

What is the force per meter of length of a straight wire carrying a 3.40A current when placed at an angle of 40° to a 0.75T unifotm magnetic field?....(please help me by showing the working)

Expert's answer

Sinse** F = B I L sin α,** force per meter is** **

F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.

F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.

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