# Answer to Question #2434 in Electromagnetism for Ian Kinyanjui

Question #2434

What is the force per meter of length of a straight wire carrying a 3.40A current when placed at an angle of 40° to a 0.75T unifotm magnetic field?....(please help me by showing the working)

Expert's answer

Sinse

**F = B I L sin α,**force per meter is

F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.

F/L = BI sin α = 0.75 * 3.4 * sin 40 = 1.64 N/m.

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment