Answer to Question #21865 in Electromagnetism for divya rawal
F = 2*F1*cos\alpha = 2*F1*d/r = 2kqQd/r^3.
r = sqrt(d^2 + R^2/4).
Differentiate F by d: F' = 2kqQ* 8(R^2-8d^2)/(R^2 + 8d^2)^5/2 = 0 => d = R/2sqrt(2).
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