Question #18280

2.) an electron moving through an electric field of 500 V/m and a magnetic field of 0.10T experiences the two fields and the electron's direction of motion are mutually perpendicular what is the speed of the electron ?

Expert's answer

Lorentz force is equal to centrifugal acceleration * mass

mv^2/r = qvB

Hence

r = mv/(qB) = 9.1*10^(-31)*10^7/(1.6*10^(-19)*0.02) = 0.003м

mv^2/r = qvB

Hence

r = mv/(qB) = 9.1*10^(-31)*10^7/(1.6*10^(-19)*0.02) = 0.003м

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