Answer to Question #1622 in Electromagnetism for Kamilla
The magnitude of the electric field of the first charge is
E1 = (1/4π ε0)q1/R = - 8.99x109*3x10-6/√0.1 = - 85.29x103 [V/m]
The magnitude of the electric field of the second charge is
E2 = (1/4π ε0)q2/R = 8.99x109*6x10-6/√0.1 = 170.57x103 [V/m]
The x component of the total electric field is Ex = - 0.1/√0.1( 85.29 +170.57)x103 = - 80.91x103 [V/m]
The y component is Ey = 0.3/√0.1( 85.29-170.57)x103 = -80.91x103 [V/m]
The magnitude of the total electric field would be E2 = (Ex2+Ey2) = 2* 80.91x106 , E = 114.42 x103 [V/m], it's directed along the angle of 225 grad from the positive x-axis (tan(θ) = Ey/Ex = 1).
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