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Answer to Question #1482 in Electromagnetism for Jon

Question #1482
A negative charge of -3.0 x 10^-6 C and a positive charge of 4.0 x 10^-6 C are separated by a distance of 3mm. What is the force on the negative charge? (magnitude and direction)
Expert's answer
–°harges with opposite signs attract each other, so the Coulomb's force would be directed to the positive charge.
F = k |q1||q2|/R2 = 8.99 x109 [Nm2/C2]*|-3.0 x 10-6|[C]*|4.0 x 10-6|[C]/(3x10-3)2[m2] = 11.98 x 103 N.

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