Two charged objects separated by 21 cm have a repulsive force of 0.02 N. If the distance in charged to 7 cm, what will be be the resulting repulsive force?
1
Expert's answer
2011-01-31T12:25:59-0500
The repulsive force is F1 = kq1q2/R12
kq1q2 = F1R12 Then F2 =k q1q2/R22 = F1R12/R22 = 0.02*212/72 = 0.18 N.
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment