Answer to Question #1435 in Electromagnetism for Rooky

Question

Two electrons (-1.6 x 10^23 C) are separated by an insulator in a capacitor at a distance of 0.0001 m. What is the electronic force between these electrons? (k- 9.0 x 10^2 N m^2/ C)

Answer 1

The Coulomb force of repulsion of two elestrons is
F = k q₁ q₂ / R² = 9.0 x 10⁹ * (-1.6 x 10^-19)² / 0.0001² = 2.30400 × 10^-20 N
With k = 9.0 x 10² N m²/ C:
F = k q₁ q₂ / R² = 9.0 x 10² * (-1.6 x 10^-19)² / 0.0001² = 2.30400 × 10^-27 N