Answer to Question #83290 in Electric Circuits for Asamoah Harrison

Question

The charge on the plates of a capacitor is 8mC when the potential
between them is 4 kV. Determine the capacitance of the capacitor.

Answer 1

C=q/U=(8∙〖10〗^(-3))/(4∙〖10〗^3 )=2∙〖10〗^(-6) F=2 μF.