Answer to Question #7494 in Electric Circuits for swapnali

Question #7494
A spring is stretched 5 × 10−2 m by a force of 5 × 10−4 N. A mass of 0.01 kg is placed on the
lower end of the spring. After equilibrium has been reached, the upper end of the spring is
moved up and down so that the external force acting on the mass is given by F(t) = 20 cos wt.
Calculate (i) the position of the mass at any time, measured form the equilibrium position and
(ii) the angular frequency for which resonance occurs.
0
Expert's answer

Answer in progress...

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
APPROVED BY CLIENTS