Answer to Question #7476 in Electric Circuits for swapnali

Question #7476
A circular disc rotates on a thin air film with a period of 0.3s. Its moment of inertia about its axis of rotation is 0.06 kg m2. A small mass is dropped onto the disc and rotates with it. The moment of inertia of the mass about the axis of rotation is 0.04 kg m2. Determine the final period of the rotating disc and mass. (10
1
Expert's answer
2012-03-16T09:20:00-0400
I - moment of inertia.
I=I1+I2
T1=2pi*sqrt(I1/m1r)=>m1gr=I1*(2pi/T1)^2=26.3
T2=2pi*sqrt((I1+I2)/m1gr)={m2->0}=0.38

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