# Answer to Question #7476 in Electric Circuits for swapnali

Question #7476

A circular disc rotates on a thin air film with a period of 0.3s. Its moment of inertia about its

axis of rotation is 0.06 kg m2. A small mass is dropped onto the disc and rotates with it. The

moment of inertia of the mass about the axis of rotation is 0.04 kg m2. Determine the final

period of the rotating disc and mass. (10

axis of rotation is 0.06 kg m2. A small mass is dropped onto the disc and rotates with it. The

moment of inertia of the mass about the axis of rotation is 0.04 kg m2. Determine the final

period of the rotating disc and mass. (10

Expert's answer

I - moment of inertia.

I=I1+I2

T1=2pi*sqrt(I1/m1r)=>m1gr=I1*(2pi/T1)^2=26.3

T2=2pi*sqrt((I1+I2)/m1gr)={m2->0}=0.38

I=I1+I2

T1=2pi*sqrt(I1/m1r)=>m1gr=I1*(2pi/T1)^2=26.3

T2=2pi*sqrt((I1+I2)/m1gr)={m2->0}=0.38

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