Question #41557

Calculate the electric power which must be supplied to the filament of of a light bulb operating at 3000K. The total surface area of the filament is

8×10−6m2 and its emissivity is 0.92.

20.3W

33.8W

46.4W

56.7W

8×10−6m2 and its emissivity is 0.92.

20.3W

33.8W

46.4W

56.7W

Expert's answer

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