Question #3837

A wire 75 cm long carrying a current of 6.0 A is at right angles to a uniform magnetic field. The magnitude of the force acting on the wire is 0.60 N. What is the strength of the magnetic field ?

Expert's answer

According to the Ampere's law:

F=B*I*L*sinA.,

where

F - the Ampere's force,

B - strength of the magnetic field,

I - amperage in a wire,

L - length of a wire,

A - angle between the amperage and the vector of magnetic field

As the wire is at the right angles, we will get that:

sinA=1,

B=F/(I*L)

B=0.6/(6*0.75)=0.13 (tesla)

The strength of the magnetic field is 0.13 tesla.

F=B*I*L*sinA.,

where

F - the Ampere's force,

B - strength of the magnetic field,

I - amperage in a wire,

L - length of a wire,

A - angle between the amperage and the vector of magnetic field

As the wire is at the right angles, we will get that:

sinA=1,

B=F/(I*L)

B=0.6/(6*0.75)=0.13 (tesla)

The strength of the magnetic field is 0.13 tesla.

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