Question #3827

A generator in a power plant develops a maximum voltage of 170 V.
<br>a. What is the effective voltage?
<br>b. A 60 W light bulb is placed across the generator. A maximum current of 0.70 A flows
through the bulb. What effective current flows through the bulb?
<br>c. What is the resistance of the light bulb when it is working?

Expert's answer

a. Effective voltage is V_{max}/√2 = 170/√2= 120.2 V

b. Effective current is I_{max}/√2= 0.7/√2 = 0.49 I

c. The resistance is R = 2W/I_{max}^{2} from the law W = I^{2}/R = I_{max}^{2} /2R

R = 2*60 / 0.7^{2} = 244.89 Ohm

b. Effective current is I

c. The resistance is R = 2W/I

R = 2*60 / 0.7

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