# Answer to Question #35837 in Electric Circuits for moses

Question #35837

The half-life of a certain radioactive isotope is 32 hours. What fraction of the sample would remain after 16 huors? a. 0.50 b. 0.25 c. 0.62 d. 0.71

Expert's answer

The formula for radioactive decay is

N=N0 * (1/2)^(t/tau)

where N0 is initial quantity of isotope and tau is half-life.

so we find

N/N0 = (1/2)^(t/tau) = (1/2)^(1/2) = 0.71

Answer is d. 0.71

N=N0 * (1/2)^(t/tau)

where N0 is initial quantity of isotope and tau is half-life.

so we find

N/N0 = (1/2)^(t/tau) = (1/2)^(1/2) = 0.71

Answer is d. 0.71

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