The current in a conductor varies as follows : during the first 8 secs there is a linear change from zero to 4 amp; during the next 15 sec the current is constant at 4 amp, during the third period of 20 secs the current decreases linearly to 3 amp. Determine (a) the total charge transferred in the elapsed time of 43 secs, (b) the average current.
We have to find the equation that describes I=f(t) and then integrate to find the total charge as the sum of the charge for the three pars of the process (a, b, and c):
Then, we can calculate the average current as:
In conclusion, we find that
(a) the total charge transferred
in the elapsed time of 43 secs is =146 C,
and (b) the average current is <I>=3.395 A.