Answer to Question #235502 in Electric Circuits for maymay2902

Question #235502

The current in a conductor varies as follows : during the first 8 secs there is a linear change from zero to 4 amp; during the next 15 sec the current is constant at 4 amp, during the third period of 20 secs the current decreases linearly to 3 amp. Determine (a) the total charge transferred in the elapsed time of 43 secs, (b) the average current.


1
Expert's answer
2021-09-10T12:17:42-0400

We have to find the equation that describes I=f(t) and then integrate to find the total charge as the sum of the charge for the three pars of the process (a, b, and c):






Then, we can calculate the average current as:


In conclusion, we find that

(a) the total charge transferred

in the elapsed time of 43 secs is =146 C,

and (b) the average current is <I>=3.395 A.


Reference:

  • Sears, F. W., & Zemansky, M. W. (1973). University physics.

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