Question #19186

A 6.82 kg bowling ball moves at 4.29 m/s. How fast must a 2.36 g Ping-Pong ball move so that the two balls have the same kinetic

energy?

Answer in units of m/s

energy?

Answer in units of m/s

Expert's answer

The kinetic energy is K=(mV^2)/2

Let x m/s is the velocity of Ping- Pong ball. If the kinetic energies are the

same then:

6.82*(4.29)^2/2=0.00236*x^2/2

x^2=6.82*(4.29)^2/0.00236=53184.7

x=230.6 m/s

Let x m/s is the velocity of Ping- Pong ball. If the kinetic energies are the

same then:

6.82*(4.29)^2/2=0.00236*x^2/2

x^2=6.82*(4.29)^2/0.00236=53184.7

x=230.6 m/s

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