Answer to Question #15836 in Electric Circuits for gabby
P = UI ==> I = P/U = 550[W]/230[V] ≈ 2.39[A].
Let's find the resistance of a heater:
P = I²R ==> R = 550[W]/(2.39[A])² ≈ 96.29[Ω].
The current consumption when plugged into a 120-V electrical outlet will be
I = U/R = 120[V]/96.29[Ω] ≈ 1.25[A].
So, the power output of the heater when plugged into a 120-V electrical outlet will be
P = I²R = (1.25[A])² * 96.29[Ω] ≈ 150[W].
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