Question #15251

What was the initial speed of a car that required 13.7 m to stop in 4.00s?

Expert's answer

We know that

V = at,

where V is velocity, a is acceleration and t is the time of acceleration. Also we know that

L = at²/2 ==> a = 2L/t²,

where L is the stop distance. So, the initial speed of a car was

V = at = (2L/t²)*t = 2L/t = 2*13.7[m]/4.00[s] = 6.85 m/s.

V = at,

where V is velocity, a is acceleration and t is the time of acceleration. Also we know that

L = at²/2 ==> a = 2L/t²,

where L is the stop distance. So, the initial speed of a car was

V = at = (2L/t²)*t = 2L/t = 2*13.7[m]/4.00[s] = 6.85 m/s.

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