Answer to Question #15251 in Electric Circuits for Chad
What was the initial speed of a car that required 13.7 m to stop in 4.00s?
We know that
V = at,
where V is velocity, a is acceleration and t is the time of acceleration. Also we know that
L = at²/2 ==> a = 2L/t²,
where L is the stop distance. So, the initial speed of a car was
V = at = (2L/t²)*t = 2L/t = 2*13.7[m]/4.00[s] = 6.85 m/s.