Answer to Question #106625 in Electric Circuits for Muhammad saad bhatti

Question

Positive charge Q is placed on a conducting spherical shell of inner radius R1 outer radius R2.A particle with charge q is placed at center of cavity.The magnitude of electric field at a point from cavity at a distance r from center is?

Answer 1

According to Gauss's theorem $E \times 4 \times pi \times r^{2} = \frac{q\times r^3}{r_0\times R^3}$

$E=\frac{q\times r}{4 \pi \times R^3 \times e_0}$