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Elastic collision cross section Qel(E) = 1.59x10-19 m2 (E/E*) if E<E* = 11.55 eV
= 1.59x10-19 m2 sqrt(E*/E) if E>E* = 11.55 eV
Ionization cross section Qion(E) = 0 if E<Ei = 15.9 eV= 3.18x10-20 m2 log(E/Ei) (Ei/E) if E>Ei = 15.9 eV
Assuming a Maxwell-Boltzmann distribution function for electrons, plot the following quantities as a function of the electron temperature in a range from 1 to 10 eV for a plasma at 100 Pa and Tgas = 300K:
1) The average elastic collision frequency
2) The average ionization frequency
Is it that it converts only when a conservative force works on it?
Eg a ball falling down has KE
Because it's PE is converting into KE
Why doesn't Conservative force store KE directly instead of converting PE into KE?
I want to ask that if a conservative force does work directly then PE can't be stord?
This I understood from ans given by you
But what happens when I stop where does that KE go
And where PE is utilised
of 8.00 m/s at an angle of 20.0° below the horizontal. It strikes the ground 3.00 s later.
(a) How far horizontally from the base of the building does the ball strike the ground?
(b) Find the height from which the ball was thrown.
(c) How long does it take the ball to reach a point 10.0 m below the level of launching?
(1) F=–YZ i–XZ j–XY k
But when I start moving by holding it in the same position at the same height what energy conversions take place
What happens to that potential energy??