a 300g ball rolls down a hill that is 1.4 m high. At the bottom of the hill, the ball has a speed of 7.6 m/s. Determine the speed of the ball at the top of the hill
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Expert's answer
2019-05-14T09:53:42-0400
Energy conservation law tells us that
"\\frac{mu^2}{2} +mgh = \\frac{mv^2}{2}"
where v is speed at the bottom of the hill, u is the speed at the top of the hill. Therefore
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