Question

you drop a stone in a well and hear it hit the bottom in 6.19s how deep is the well

Answer 1

Let the depth of well is L. The total time

$$t=t_1+t_2=\sqrt{\frac{2L}{g}}+\frac{L}{c}$$

So, we have an equation

$$6.19=\sqrt{\frac{2L}{9.8}}+\frac{L}{340}$$

Solution

$$L=160\:\rm{m}$$