Answer to Question #78302 in Classical Mechanics for Thomas

Question

A passenger is on a train moving at a constant forward velocity. The passenger jumps in an upward trajectory. Does the passenger land in the same spot from which he jumped? Or does the passenger lose forward momentum, not being self-propelled, and land behind the spot from which he jumped? What if the train travels at 1000 mph and the passenger jumps 10 miles high? How far (if at all) from the spot that he jumped from will he land?

Answer 1

The passenger loses forward momentum, not being self-propelled, and land behind the spot from which he jumped.
v=1000 mph=( 0.44704)1000 m/s.
t=2√(2h/g)=2√(2(10)(1609.34)/9.8) s.
d=vt=((0.44704)1000)(2√(2(10)(1609.34)/9.8))= 51239 m.
d=31.8 miles.