Question #72135

A 500 g can of food is given a push on a frictionless level surface and is observed to accelerate at a rate of 1.5 m/s^2. How much is the force in Newton’s, was applied to accelerate the can of food?

Expert's answer

Solution

From the 2nd Newton’s law:

F=ma.

F=(0.5)(1.5)=0.75 N.

Answer: 0.75 N.

From the 2nd Newton’s law:

F=ma.

F=(0.5)(1.5)=0.75 N.

Answer: 0.75 N.

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