Answer to Question #179357 in Classical Mechanics for Kristen Tyler

Classical Mechanics

Question #179357

A car slows from 23.69 m/s to rest in 4.44 s. How far did it travel in this time?

Expert's answer

Answer

Using

v=u+at

"0=23.69-a\\times4.44\\\\a=5.35m\/s^2"

So travelled distance

"S=\\frac{v^2-u^2}{2a}\\\\=\\frac{0-23.69^2}{-2\\times5.35}\\\\=52.45m"

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