A bullet leaves the barrel of a gun at a speed of 220 m/s at an angle of 10 degrees above the horizontal. At the moment the bullet leaves the barrel, the acceleration of the bullet is:
0
220 m/s2 to the right
9.8 m/s2 upward
9.8 m/s2 downward
1
Expert's answer
2021-01-19T20:00:18-0500
At the moment the bullet leaves the barrel, the bullet moves under the gravity only. Therefore, the acceleration of the bullet equals 9.8 m\s2 directed downward.
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