Question

A 72.0 kg box slides down a 30.0◦
ramp with
an acceleration of 3.10 m/s2
.
72 kg
µk
3.1 m/s
2
30◦
Find µk between the box and the ramp.
The acceleration of gravity is 9.81 m/s
2
.

Answer 1

The acceleration will be

$$a=g\sin{30}-\mu g \cos{30}$$

$$3.1=9.81(\sin{30}-\mu \cos{30})$$

$$\mu=0.212$$