Answer to Question #96216 in Atomic and Nuclear Physics for Kharis Eyebiokin

Question

The density of copper is 8.9*10^3 kg/m^3, and each copper atom has a mass if 63u (1u=1.6605*10^-27kg.) Estimate the average distance between the centers of the neighboring copper atom?

Answer 1

l=(ρ*1000*N_a/M)^-1/3

I=(8.9*10³*1000/63)*6.022*10²³)^-1/3=22.7*10^-9 m = 22.7 nm.

I - distance between atoms

ρ - density

M - molar mass

N_a – Avogadro number