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The volume of an iceberg is 664,000 ft^3.

(a)

What is its weight (in lb), assuming it is pure ice? (Round your answer to at least four significant figures.)

____ lb

(b)

What is the volume of seawater (in ft^3) it displaces when floating? (Hint: You know what the weight of the seawater is. Round your answer to at least three significant figures.)

____ ft cubed

(c)

What is the volume of the part of the iceberg out of the water (in ft^3)?

____ ft cubed

Thank you for the help!

t

A juniper-wood plank measuring 0.46 ft by 1 ft by 14 ft is totally submerged in water.

(a) What is its weight?

_____ lb

(b) What is the buoyant force acting on it?

_____ lb

(c) What is the size and the direction of the net force on it?

size

_____ lb

... direction up or down?

A large tanker truck can carry 21 tons (42,000 lb) of liquid.

(a)

What volume of antifreeze (in ft^3) can it carry?

_____ f^t3

(b)

What volume of pure water (in ft^3) can it carry?

_____ ft^3

A certain part of an aircraft engine has a volume of 1.6 ft^3.

(a) Find the weight of the piece when it is made of silver.

____ lb

(b) If the same piece is made of aluminum, what is its weight?

____ lb

Determine how much weight is saved by using aluminum instead of silver.

____ lb

A box-shaped metal can has dimensions 14 in. by 4 in. by 5 in. high. All of the air inside the can is removed with a vacuum pump. Assuming normal atmospheric pressure outside the can, find the total force (in lb) on one of the 4-by-5 in. sides. (Enter the magnitude.)

______lb

R/X

0 = (2e+ i)n~~ = n(~ + A)’ (11.34)

e= o

in which all partial waves

are completely absorbed up to

d= R/X (qe= 0 for complete absorption)

and unaffected for

t‘> R/X ( qe = l), then

uSc = T(R + A)’

(11.49)

and

so that

ur =’a@ + A)’

(11 -50)

ut = 2v(R + A)’ (11.51)

derive black disk scattering

E4 transitions are 44Sc, 52Mn,

86Rb, 93MO,141n, and 202Pb. Look up the partial lifetimes for these

transitions from collections of spectroscopic data, and compare with values

calculated from the Weisskopf estimates.